derive velocities expression after collusion?
Answers
Explanation:
Let two bodies of masses m1 and m2 moving with velocities u1 and u2 along the same straight line.
And consider the two bodies collide and after collision v1 and v2 be the velocities of two masses.
Before collision
Momentum of mass m1=m1u1
Momentum of mass m2=m2u2
Total momentum before collision
p1=m1u1+m2u2
Kinetic energy of mass m1=21m1u12
Kinetic energy of mass m2=21m2u22
Thus,
Total kinetic energy before collision is
K.E=21m1u12
hope it will helpful to you give thanks to my answer nd follow me
be happy nd take care of yourself...
happy lohri dear ❤❤✌✌✌✌
Answer:
Explanation:
Let two bodies of masses m1 and m2 moving with velocities u1 and u2 along the same straight line.
And consider the two bodies collide and after collision v1 and v2 be the velocities of two masses.
Before collision
Momentum of mass m1=m1u1
Momentum of mass m2=m2u2
Total momentum before collision
p1=m1u1+m2u2
Kinetic energy of mass m1=21m1u12
Kinetic energy of mass m2=21m2u22
Thus,
Total kinetic energy before collision is
K.E=21m1u1