Physics, asked by gamingbbcc, 9 months ago

Derive velocity-time relation and position-time relation for a uniformly accelerated motion by graphical method.

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Answered by hangma75

Answer:

Consider the graph shown in the given attachment. Obviously, the total distance s travelled by the object in time t is given by are under v-t graph. Obviously, OABGC is a trapezium, whose area is (OA + BC/2) × OC. Therefore, this equation is the position velocity relation for uniformly accelerated motion.

Explanation:

hopes it helps you.

Answered by Anonymous

Answer:

I dont know the answere

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