Physics, asked by mansimar123rklp66qhg, 1 year ago

derive weight on moon=1/6 of weight on earth

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Answered by Anonymous
0

 =  \frac{g \: of \: earth \times m}{g \: of \: moon \times m}  \\   = \frac{ \frac{6.674 \times  {10}^{ - 11}  \times 5.972 \times  {10}^{24} }{ {(6.3781 \times  {10}^{6} )}^{2} } }{ \frac{6.647 \times  {10}^{ - 11}  \times 7.347 \times  {10}^{22} }{ {(1.738 \times  {10}^{6} )}^{2} } }  \\  =  \frac{ \frac{39.857 \times  {10}^{13} }{44.060 \times  {10}^{12} } }{ \frac{49.033 \times  {10}^{11} }{3.020 \times  {10}^{12} } }  \\  =  \frac{0.9046 \times 10}{16.236 \times  {10}^{ - 1} }  \\  =  \frac{9.046}{1.6236}  \\  =  \frac{5.571}{1} or \: 6 : 1
This proves that Weight on earth is six times greater than on moon.
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