Derive [(x-y) 2(x+y)2]2
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( x - y )² × ( x + y )²
= ( x² - 2xy + y² ) ( x² + 2xy + y² )
= x² ( x² + 2xy + y² ) - 2xy ( x² + 2xy + y² ) + y² ( x² + 2xy + y² )
= x⁴ + 2x³y + x²y² - 2x³y - 4x²y² - 2xy³ + x²y² + 2xy³ + y⁴
= x⁴ - 2x²y² + y⁴
= ( x² )² - 2.x².y² + ( y² )²
= ( x² - y² )²
= [ ( x + y ) ( x - y ) ]²
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