Physics, asked by sydigital777, 1 month ago

Derived and expression for the resolution of vector.give me ans

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Answered by samyameendra2006

derive the expressions for magnitude of its components, hence prove thatt tan theta= Ay / Ax and A = square root Ax2+Ay2,whereAx Ay are magnitudes of its XY components respectively and 'theta" is angle made by A with positive X-direction. Similarly the projection of A on y-axis is OQ.

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