dervitieve of sin^-1(√1+x^2/2) please explain also
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Step-by-step explanation:
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Answer:
X=0.
Step-by-step explanation:
sin^-1 is also 1/ sin .
as according to the question :-->.
1/ sin [1+ x square /2].
1/sin [(2+ x square) /2].
2+x square / 2sin .
2+x square=0.
x square= -2
x = root -2 .
but this contrast that in the inner side of root don't have minus sign.
so, the value of x is 0 .
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