descibe the mirror formula class 10
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mirror formula
1/f=1/v+1/u
and lens formula
1/f= 1/v-1/u
where f= focal length
v= image distance
u= object distance
both formula have difference of sign so don't confuse Thanks
1/f=1/v+1/u
and lens formula
1/f= 1/v-1/u
where f= focal length
v= image distance
u= object distance
both formula have difference of sign so don't confuse Thanks
Answered by
2
Hey mate
Mirror formula is the relationship between object distance (u), image distance (v) and focal length.
1v+1u=1f1v+1u=1f
proof of mirror formula:

In ΔABCΔABC and ΔA′B′C′ΔA′B′C′
ΔABCΔABC ∼∼ ΔA′B′CΔA′B′C [AA similarity]
ABA′B′=ACA′C′ABA′B′=ACA′C′ ⋯⋯(1)
Similarly, In ΔFPEΔFPEand ΔA′B′F′ΔA′B′F′
EPA′B′=PFA′FEPA′B′=PFA′F
ABA′B′=PFA′FABA′B′=PFA′F [ AB=EP] ⋯⋯(II)
From (i) &(ii)
ACA′C=PFA′FACA′C=PFA′F
=>A′CAC=A′FPF=>A′CAC=A′FPF
=>(CP−A′P)(AP−CP)=(A′P–PF)/PF=>(CP−A′P)(AP−CP)=(A′P–PF)/PF
Now, PF=−f;CP=2PF=−2fPF=−f;CP=2PF=−2f ; AP=−uAP=−u ; and A′P=−vA′P=−v
Put these value in above relation:
⟹[(−2f)–(−v)](−u)−(−2f)=[(−v)–(−f)](−f)⟹[(−2f)–(−v)](−u)−(−2f)=[(−v)–(−f)](−f)
⟹uv=fv+uf⟹uv=fv+uf
⟹1f=1u+1v
Mirror formula is the relationship between object distance (u), image distance (v) and focal length.
1v+1u=1f1v+1u=1f
proof of mirror formula:

In ΔABCΔABC and ΔA′B′C′ΔA′B′C′
ΔABCΔABC ∼∼ ΔA′B′CΔA′B′C [AA similarity]
ABA′B′=ACA′C′ABA′B′=ACA′C′ ⋯⋯(1)
Similarly, In ΔFPEΔFPEand ΔA′B′F′ΔA′B′F′
EPA′B′=PFA′FEPA′B′=PFA′F
ABA′B′=PFA′FABA′B′=PFA′F [ AB=EP] ⋯⋯(II)
From (i) &(ii)
ACA′C=PFA′FACA′C=PFA′F
=>A′CAC=A′FPF=>A′CAC=A′FPF
=>(CP−A′P)(AP−CP)=(A′P–PF)/PF=>(CP−A′P)(AP−CP)=(A′P–PF)/PF
Now, PF=−f;CP=2PF=−2fPF=−f;CP=2PF=−2f ; AP=−uAP=−u ; and A′P=−vA′P=−v
Put these value in above relation:
⟹[(−2f)–(−v)](−u)−(−2f)=[(−v)–(−f)](−f)⟹[(−2f)–(−v)](−u)−(−2f)=[(−v)–(−f)](−f)
⟹uv=fv+uf⟹uv=fv+uf
⟹1f=1u+1v
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