Question

describe a method for estimating the area of ​

Answer 1

Step-by-step explanation:

I tried to consider simple shapes that can "fill" the given one as much as possible:

I got two trapeziums (one blue and the other red) and one triangle (red). the area of the trapezium is:

So:

So:Area

So:Areablue

So:Areablue=

So:Areablue=1

So:Areablue=12

So:Areablue=12(

So:Areablue=12(2

So:Areablue=12(2+

So:Areablue=12(2+3

So:Areablue=12(2+3)

So:Areablue=12(2+3)⋅

So:Areablue=12(2+3)⋅5

So:Areablue=12(2+3)⋅5=

So:Areablue=12(2+3)⋅5=12.5

So:Areablue=12(2+3)⋅5=12.5u.a.

So:Areablue=12(2+3)⋅5=12.5u.a.

So:Areablue=12(2+3)⋅5=12.5u.a. Area

So:Areablue=12(2+3)⋅5=12.5u.a. Areared

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=1

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=12

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=12(

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=12(4

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=12(4+

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=12(4+2

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=12(4+2)

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=12(4+2)⋅

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=12(4+2)⋅5

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=12(4+2)⋅5+

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=12(4+2)⋅5+1

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=12(4+2)⋅5+12

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=12(4+2)⋅5+12(

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=12(4+2)⋅5+12(1

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=12(4+2)⋅5+12(1⋅

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=12(4+2)⋅5+12(1⋅4

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=12(4+2)⋅5+12(1⋅4)

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=12(4+2)⋅5+12(1⋅4)=

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=12(4+2)⋅5+12(1⋅4)=17

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=12(4+2)⋅5+12(1⋅4)=17u.a.

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=12(4+2)⋅5+12(1⋅4)=17u.a.We get:

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=12(4+2)⋅5+12(1⋅4)=17u.a.We get:Area

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=12(4+2)⋅5+12(1⋅4)=17u.a.We get:Areatotal

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=12(4+2)⋅5+12(1⋅4)=17u.a.We get:Areatotal=

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=12(4+2)⋅5+12(1⋅4)=17u.a.We get:Areatotal=12.5

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=12(4+2)⋅5+12(1⋅4)=17u.a.We get:Areatotal=12.5+

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=12(4+2)⋅5+12(1⋅4)=17u.a.We get:Areatotal=12.5+17

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=12(4+2)⋅5+12(1⋅4)=17u.a.We get:Areatotal=12.5+17=

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=12(4+2)⋅5+12(1⋅4)=17u.a.We get:Areatotal=12.5+17=29.5

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=12(4+2)⋅5+12(1⋅4)=17u.a.We get:Areatotal=12.5+17=29.5u.a.

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=12(4+2)⋅5+12(1⋅4)=17u.a.We get:Areatotal=12.5+17=29.5u.a.

So:Areablue=12(2+3)⋅5=12.5u.a. Areared=trapezium+triangle=12(4+2)⋅5+12(1⋅4)=17u.a.We get:Areatotal=12.5+17=29.5u.a. [u.a. = unit of area]

Answer 2

Hope it will help you Mark