Describe an activity to test conduction of electricity in liquid show experiment
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Hey buddy here's ur answer.
Electrical conductivity of liquids can be tested by a simple activity of taking a liquid, like lemon juice, in a container, inserting electrodes in it, connecting the two electrodes to the terminals of a battery with a bulb (LED) between them. The bulb glows, indicating that lemon juice is a conductor of electricity.
Explanation:
- Take a small beaker.Fix two iron nails on a rubber cork about 1 cm apart and place this cork in the beaker.
- The two iron nails will act as the two electrodes.
- Connect the two nails to the two terminals of a battery by including a torch bulb and switch in the circuit.
- Pour a solution of dilute hydrochloric acid in the beaker carefully. Now pass electric current through the hydrochloric acid solution by closing the switch.
- We will observe that as soon as we switch on the current ,the bulb starts glowing.
- The bulb can glow only if the hydrochloric acid solution taken in the beaker conducts electricity. So the glowing of bulb this case tells us that hydrochloric acid solution conducts electricity.
- Repeat this activity by taking sulphuric acid solution, sodium hydroxide solution ,common salt solution ,copper sulphate solution ,vinegar and lemon juice in the beaker. The bulb glow again. This shows that all these solutions are conducting liquid.
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Explanation:
Well liquid do not conduct electricity because in liquid electricity is carried by ± ion so the liquid must have to loss or gain electrons to from ±ion so as to conduct electricity
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