Question

Describe an experiment to find the resistance of a coil with the help of ammeter and voltmeter.

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Answer 1

Heya friend!!
Rajdeep here...

=> Chemistry Lavoisier
=> Brainly Benefactor

Your answer:
Make the circuit first by a Battery, voltmeter, ammeter, resistor, and a switch. Put the voltmeter in parallel to the resistor and ammeter in series.

Since, voltmeter has high resistance, if it is connected in series, it will consume almost all the voltage, so it is connected in parallel.

Ammeter is a device with less resistance, so if it is connected in parallel, it will draw huge current and give incorrect reading. Hence, it is connected in series.

A switch is essential because a limitation of Ohm's Law is that, temperature must be constant. If you keep the switch on for a long time, heat is generated in the wire, so you will get improper reading.

Now, switch on the switch. Note the reading on the ammeter and voltmeter. Switch off the switch and note them down.
According to ohm's law,
V = IR
Where V is the Potential difference, I is the current and R is the resistance.

Put the values of V (from voltmeter) and I (from ammeter) to calculate the resistance...

Where R = V/I

Thanks!!
Hope my answer is satisfactory!!

Answer 2

Hello friend
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First,

Apparatus: Two unknown resistance,Battery,Plug keys,D.C Voltmeter,D.C Ammeter,electrical wires.

Now let's move to the procedure

Procedure:

1.) First not the zero error and the least count of the voltmeter and ammeter having proper range.

2.) Connect the electric circuit as shown in the in the diagram.Take proper precautions while touching the materials because that material can harm you so take care for that.

3.) Close the plug key and allow the electric current pass through the circuit.

4.) Adjust the variable resistance to increase the resistance till the expected reading is obtained on the ammeter .

5.) Note the voltmeter reading and open the circuit by opening the plug key.

6.) Repeat the same procedure at least 3 or 4 times and take minimum 3 readings.

So,now I am going to show some readings which I have observed in the class laboratory with finding the resistance.

Readings:

1.) Ammeter Reading (I) in Ampiere(A)

i) 24mA.
ii) 48mA.
iii) 72mA.

2.) Voltmeter Readings (V) in Volt(v)

i) 1.6v
ii). 2.6v
iii). 3v

So,we have observed some readings.

Now we calculate the resistance

As we all know that,

R = V/I

⭐ So in first reading the resistance will be

I = 24mA.

= 0.024A.

and V = 1.6v

By using the formula,

R = V/I

R = 1.6/0.024

R = 16 x 10^-1/24 x 10^-3

R = 16 x 10^-1 x 10^3/24

R = 16 x 10^2/24

R = 16 x 100/24

R = 1600/24

R = 66.6 Ohm

⭐ In second reading..

I = 48mA
= 0.048A.

and

V = 2.6v

By using the formula,

R = V/I

R = 2.6/0.048

R = 26 x 10^-1/ 48 x 10^-3

R = 26 x 10^-1 x 10^3/48

R = 26 x 10^2/48

R = 26 x 100/48

R = 2600/48

R = 54.1 ohm.


⭐ In third reading..

I = 72mA

= 0.072A.

and

V = 3v

By using the same formula,

R = V/I

R = 3/0.072

R = 3/72 x 10^-3

R = 3 x 10^3/72

R = 3 x 1000/72

R = 3000/72

R = 41.6 ohm.

So, we got the resistance of 66.6 ohm and 54.1 ohm and 41.6 ohm. respectively.

I hope this will helps you..

Thanks.