Question

Describe an experiment to show:

1.Electrolysis of water
2.Laws of reflection of light ​

Answer 1

Answer:

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Take a glass beaker fix two electrodes. The positive electrode acts as anode &negative electrode act as cathode. Fill 1/3 of beaker with water. ... Oxygen gas is evolved at anode and hydrogen gas released at cathode.

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(i) The incident ray, the reflected ray and the normal at the point of incidence, lie in the same plane. (ii) The angle of incidence and angle of reflection are equal i.e. ∠i = ∠r. Take a wooden drawing board and fix a white sheet of paper on it. In the middle of paper draw a straight line KK\ Mark a point B on it.

$\mathcal{hope \: it \: helps \: you}$

Answer 2

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Question ⤵

Describe an experiment to show

• Electrolysis of water

Answer ⤵

The process of breaking down of water molecules by the passage of electric current is known as electrolysis of water. Electrolysis of Water:

• A glass beaker is fixed with two carbon electrodes and it is filled with water up to one third of its volume.

• The positive carbon electrode acts as anode and the negative carbon electrode acts as cathode.

• Two test tubes are placed on the electrodes.

• The electrodes are connected to a battery’ and current is passed until the test tubes are filled with a particular gas.

• If the gas collected is tested using a burning splint we can notice that the gas in cathode side bums with a popping sound when the burning splint is brought near the mouth of the test tube.

• This property is usually shown by hydrogen gas and so it is confirmed that the gas inside the test tube is hydrogen.

• The burning splint placed near the anode side bums more brightly confirming that it is oxygen gas. This experiment shows that water is made up of hydrogen and oxygen.

• The ratio of hydrogen and oxygen is 2:1. Hence, for every two volumes of hydrogen collected at the cathode, there is one volume of oxygen collected at the anode

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Question ⤵

Describe an experiment to show:

• Laws of reflection of light

Answer ⤵

• The incident ray, the reflected ray and the normal at the point of incidence, lie in the same plane.

• The angle of incidence and angle of reflection are equal i.e. ∠i = ∠r.

• Take a wooden drawing board and fix a white sheet of paper on it. In the middle of paper draw a straight line KK\ Mark a point B on it.

• fix two steel pins P and Q on the straight line AB atleast 10 cm a part look for the images of thr pins P and Q and fix two pins P Q such that PQ and images of P and Q are all in the same straight line. Remove the pins and draw small circles around the pin pricks.

• Remove the mirror also join PQ and produced the straight line to meet at B .Measure <ABN = i and <CBN = r

• It is found that <i = <r this proves that the angel of incidence is equal to angle of Reflection .

• As the incident ray the reflected ray and the normal lie in the plane of paper therefore they lie in the same plane.

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$\huge\fbox\red{Thank you :)}$