Question

describe an experiment to show how a simple pendulum could be calibrated to measure time in seconds​

Answer 1

Answer:

Time period of the simple pendulum (measured in seconds.) is given by formula,

T=2π

g

l

=

30oscillations

Timefor30occilations

⟹g=4π

2

L/t

2

Sterp:1 Measure length of pendulum to the middle of pendulum bob.

Step:2 Set the pendulum in motion until it completes 30 to and from oscillations taking care to record this time. Then time period T for one oscillation is is the number recorded divided by 30.

Step:3 Take total of eight measurements for g$ using two different masses.at 4 different values for the length L.

Answer 2

Answer:

Time period of the simple pendulum (measured in seconds.) is given by formula,

T=2π*(root of (l/g)

= Time for 30 oscillations ÷ 30 occilations

⟹g=4π^2L/t^2

Step :1 Measure length of pendulum to the middle of pendulum bob.

Step:2 Set the pendulum in motion until it completes 30 to and from oscillations taking care to record this time. Then time period T for one oscillation is is the number recorded divided by 30.

Step:3 Take total of eight measurements for g$ using two different masses.at 4 different values for the length L.