Describe an experiment to verify Archimedes' principle
Answers
Answer:
Experiment to verify Archimedes' principle:
∙ Suspends a solid by a thin thread from the hook of a balance. Make note of its weight.
∙
Fill a eureka can with water up till its spout. St up a cylinder below the spout of the eureka as observed in the diagram. Gently, submerged the solid in water and collect the displaced water in the measuring cylinder.
∙ Make note of the weight of the liquid and the volume of the water is assemble in the measuring cylinder once the water dripping through the spout.
∙ It is clear from the diagram that the volume of the water displaced is equivalent to the difference of weight in air to the weight in water i.e.,
Weight in air-weight in water - volume of water
⇒ 300gf−200gf=100gf
⇒ Volume of water displaced is equal to the volume of solid which is equivalent to 100cm^3
⇒ As we known that the density of water is 1 gcm^−3
⇒ Hence the weight of the water displaced is equivalent to the loss in weight or the upthrust =100gf
⇒ Hence the Archimedes' principle is verified.
Answer:
Take a stone of known volume with density greater than water and hang it with a spring weighing balance. Record the mass m (=W
1
) and volume V. Now lower the system of stone and weighing balance into water slowly such that the stone is completely immersed in water (weighing machine is not immersed). Note the new reading of the weighing machine m
2
(=W
2
). It is observed that m
2
<m suggesting the existence of an upward force.
Calculate Upthrust = Difference in weights, ΔW=(m−m
2
)g
Calculate weight of water displaced, W
w
=ρ
w
Vg
It is observed that ΔW=W
w