Physics, asked by jdas70042, 6 hours ago

Describe Carnot engine and obtain an expression for its efficiency​

Answers

Answered by Rajendar64Kishore
0

Answer:

Here, e is the efficiency of the Carnot cycle. Therefore, the Carnot cycle is a reversible, thermodynamic cycle which has four main processes and its efficiency is e=1−T2T1. Note: In isothermal processes temperature remains constant while in adiabatic processes heat remains constant.

Answered by chanshi27
0

Answer:

A carnot engine is a reversible heat engine operating between two temperatures,

The steps involved in a carnot cycle are explained as follows.

Step 1:

Isothermal expansion of gas from state (P

1

,V

1

,T

1

) to state (P

2

,V

2

,T

2

) as shown in the figure.

Step 2:

Adiabatic expansion of gas from (P

2

,V

2

,T

1

) to (P

3

,V

3

,T

2

)

Step 3:

Isothermal compression of gas from (P

3

,V

3

,T

2

) to (P

4

,V

4

,T

2

)

step 4:

Adiabatic compression of gas from (P

4

,V

4

,T

2

) to (P

1

,V

1

,T

1

)

These steps constitute one carnot cycle.

The process is repeated thereafter.

The efficiency of carnot engine, η is given by

η=

Q

1

Q

1

−Q

2

=

T

1

T

1

−T

2

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