Question

Describe force on a current-carrying conductor in a magnetic field

Answer 1

$\large{\underline{\boxed{ Answer}}}$

Welcome to the concept of Kicking wire Experiment.

According to this experiment :-

A current carrying conductor kept perpendicular in a magnetic field experiences a force on it .

★This is due to the interaction of two magnetic field lines produced by a current carrying conductor and magnet.

The magnitude of force is given by :-

$\boxed{\sf{ </strong><strong>F</strong><strong> </strong><strong>=</strong><strong> </strong><strong>BI</strong><strong>L</strong><strong> </strong><strong>sin</strong><strong>θ</strong><strong> </strong><strong> </strong><strong>}}$

where, B is magnetic field

I is current in conductor

L is length of conductor

Sinθ is inclination of conductor with magnetic field.

Note :- Force experienced by conductor is maximum at 90°.

The direction of force is given by Fleming's left hand rule.

According to this rule stretch your middle, right finger and thumb such that they are mutually perpendicular then middle finger gives direction of current,right finger gives direction of magnetic field and thumbs denotes the direction of motion of conductor.