Question

Describe how does the value of g vary in the following cases:

(a) above the surface of the earth (b) at poles and the equator

(c) at the surface of moon.​

Answer 1

Explanation:

In this section, we observe how Newton’s law of gravitation applies at the surface of a planet and how it connects with what we learned earlier about free fall. We also examine the gravitational effects within spherical bodies.

Weight

Recall that the acceleration of a free-falling object near Earth’s surface is approximately

g

=

9.80

m/s

2

. The force causing this acceleration is called the weight of the object, and from Newton’s second law, it has the value mg. This weight is present regardless of whether the object is in free fall. We now know that this force is the gravitational force between the object and Earth. If we substitute mg for the magnitude of

→

F

12

in Newton’s law of universal gravitation, m for

m

1

, and

M

E

for

m

2

, we obtain the scalar equation

m

g

=

G

m

M

E

r

2

where r is the distance between the centers of mass of the object and Earth. The average radius of Earth

Answer 2

Answer:

at equator it decreases as radius slightly increses.

c) At moon it decreases 6 times.

hope. it helps......