Question

Describe how to compare EMF of two cells using combination method of potentiometer​

Answer 1

Answer:

Solution :

A battery of stable emf E is used to set up a potential gradient

along a potentiometer wire (

p.d. across total length L of the wire). The positive terminals of the cells, whose emf's

and

are to be compared, are connected to the high potential terminal A. The negative terminals of the cells are connected to a galvanometer through a two-way key. The other terminal of the galvanometer is connected to a pencil jockey. The emf E should be greater than both the Now, without changing the potential gradient, point Q is connected to C, bringing cell

into the circuit. Let its null point D' be at a distance

from A, so that <br>

<br>

<br> Hence, by measuring the corresponding null lengths, the

and

, the ratio

can be calculated. The experiment is repeated for different potential gradients.

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