Question

Describe how to make 100 mL each of 0.4 M, 0.2 M and 0.1 M solution from a stock of 0.8 M. Would you use parallel or serial dilution for this?

Answer 1

Answer:

Volume of 0.8M stock solution required to make 100mL of 0.4M solution = 50mL

Volume of 0.8M stock solution required to make 100mL of 0.2M solution = 25mL

Volume of 0.8M stock solution required to make 100mL of 0.1M solution = 12.5mL

Explanation:

Given:

concentration of stock solution, c₁ = 0.8M

concentrations of the solutions to be prepared are,

c₂ = 0.4M

c₃ = 0.2M

c₄ = 0.1M

volume of each of the solutions to be prepared,

v₂ = v₃ = v₄ = 100mL

To find:

Volume of the stock solution required to make,

0.4M in 100mL, v₁ = ?

0.2M in 100mL, v₁' = ?

0.1M in 100mL, v₁'' = ?

We know that,

where,

$C_{a}$  is the concentration of stock solution

$C_{b}$  is the concentration of the solution to be prepared

$v_{a}$ is the volume of stock solution required

$v_{b}$ is the volume of the solution to be prepared

Now, using the above equation we get,

v₁ = 50mL

v₁' = 25mL

v₁'' = 12.5mL

Hence, Volume of 0.8M stock solution required to make 100mL of 0.4M solution = 50mL

Volume of 0.8M stock solution required to make 100mL of 0.2M solution = 25mL

Volume of 0.8M stock solution required to make 100mL of 0.1M solution = 12.5mL

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