Question

Describe hybridization in acetylene (C2H2) molecule. Also draw diagram of hybridized orbitals in this molecule. plz jaldi karna kal paper hay ​

Answer 1

Answer:

When we break down ethyne molecules it basically consists of 2 CH molecules. However, we will take first take both carbon and hydrogen molecule separately and draw their orbital diagrams. When we do this we will see that carbon has 6 electrons and hydrogen has one electron.

Hybridization Of C2H2

Now, if we see the electronic configuration of carbon in its ground state it will be represented as 1s2 2s2 2p2. When it gets into an excited state, one of the electron from 2s orbital will move or jump to the 2pz orbital and the electronic configuration will change to 1s2 2s1 2px12py1 2pz1. Meanwhile, the CH molecule has only 1 hydrogen atom, therefore the 2s1 and the 2pz1 orbitals get hybridised. This further leads to the formation of 4 sp hybridized orbitals wherein each CH molecule will form 2 hybridized sp orbitals.

During hybridization, C-C sigma bond is formed when one sp orbital overlaps from each of the carbons and two C-H bonds are created when second sp orbital on each carbon overlaps with 1s orbital of hydrogen. In this, the carbon atom will have two half-filled 2p orbitals. These two pairs of p orbitals do not participate in the hybridization and instead form two pi bonds resulting in the creation of a triple bond