Describe in a paragraph abot Alpha particle scattering experiment and pick out some conclusion regarding structure of atoms...
Answers
Explanation:
The Alpha Particle Scattering Experiment. They took a thin gold foil having a thickness of 2.1×10-7 m and placed it in the centre of a rotatable detector made of zinc sulfide and a microscope. Then, they directed a beam of 5.5MeV alpha particles emitted from a radioactive source at the foil.
Answer : Ernest Rutherford was interested in knowing how the electrons are arranged within an atom. Rutherford designed an experiment for this. In this experiment, fast moving alpha (α)-particles were made to fall on a thin gold foil.
He selected a gold foil because he wanted as thin a layer as possible. This gold foil was about 1000 atoms thick.
α-particles are doubly-charged helium ions. Since they have a mass of 4µ, the fast-moving α-particles have a considerable amount of energy.
It was expected that α-particles would be deflected by the sub-atomic particles in the gold atoms. Since the α-particles were much heavier than the protons, he did not expect to see large deflections. But, the α-particle scattering experiment gave totally unexpected results .
Explanation :
Conclusion about the structure of Atoms : Protons and neutrons are about the same size while electrons are much smaller. The nucleus is positively charged and consists of neutrons and protons. Electrons move around the nucleus in certain rings. The particles within the atom are held together by very strong forces.