Question

Describe iodination of methane.

Answer 1

I2reacts with ch4 - ch3i + hI
I2 reacts with ch3I -ch2I +I
I2 reacts with ch2I - chI + hI
I2 reacts with ch2I -chI + hI

Answer 2

Answer:

Explanation:

The iodination of methane is a practically impossible process.

It involves CH4 + I2 = CH3I + HI

The above reaction is a reversible reaction as HI is very strong reducing agent. When rectoion is first carried out in forward direction then the HI formed tries to reduce the CH3I and the iodine in HI tries to oxides itself from oxidation state -1 to 0. Thus the reaction goes in backward direction.  In a practical when this reaction occurs the new forming HI is immediately removed, so that the reaction can go in forward direction .

I2 --2I. is highly reversible.

CH4 + I2 -- CH3I + HI reversible

HI======H2 + I2 reversible

CH3I + HI ——- CH4 + I2