Describe jj thomson's experiment on the discovery of electrons
Answers
Answer:
JJ Thompson
Explanation:
he discovered the electrons with his famous discharge tube experiment
Answer :-
J. J. Thomson measured the ratio of electrical charge (e) to the mass of electron (m) by using cathode ray tube and applying electrical and magnetic field perpendicular to each other as well as to the path of electrons.
Thomson argued that the amount of deviation of the particles from their path in the presence of electrical or magnetic field depends upon :-
✏ The magnitude of the negative charge on particle, greater the magnitude of the charge on the particle, greater is the interaction with the electric or magnetic field and thus greater is the
reflection.
✏ The mass of the particle - lighter the particle, greater the deflection.
✏ The strength of the electrical or magnetic field - the deflection of electrons from its original oath increases with the increase in the voltage across electrodes, or the strength of the magnetic field.
★ More to know :-
• J.J. Thomson did this experiment in 1897. He was a British Physicist.
• When only electric field is applied, the electrons deviate from their path and hit the cathode ray tube.
• Similarly, when only magnetic field is applied, electron strikes the cathode ray tube at a point.
• By carefully balancing the electrical and magnetic field strength, it is possible to bring back the electron to the path followed as in the absence of electric or magnetic field and they hit the screen at a point .
Hope this answer helps you. Thanks for asking.