Question

describe motion of body which is accelerating at constant rate of 10m/s^2. If body starts from rest , how much distance will it cover in 2s

Answer 1

The distance covered in 2s is 20 meters.

Solution:

As the body is moving in constant acceleration, the motion of the body is linear.

If the body starts from rest means its initial velocity is zero which is represented mathematically as u = 0.

The acceleration is constant i.e. $a=10\ \mathrm{m} / \mathrm{s}^{2}$ and the time covered will be t = 2s.

So provided the data’s such as initial velocity, acceleration and time covered given, the distance covered in 2s can be calculated using the Newton’s third equation of motion, i.e.,

$x=u t+\frac{1}{2} a t^{2} \quad \rightarrow(1)$

By substituting the known values in (1), we get

$x=(0 \times 2)+\left(\frac{1}{2} \times 10 \times 2 \times 2\right)$

$\therefore x=20\ \mathrm{m}$

Thus, the distance covered by the body in 2s is 20 meters.

Answer 2

Explanation:

Let the initial velocity be = u = 0

Let the final velocity be = v = 0

Let the acceleration be = a = 10m/s²

Let the time be = t = 2sec

S = ut + 1/2 at^2

S = 0*2 + 1/2*10*2*2

S = 0 + 20

S = 20 m

Therefore distance travelled = 20m