describe raults law?
Answers
describe raoult's law
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ANSWER :
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RAOULT'S LAW .....
RAOULT'S LAW IS A LAW THAT RELATED THE THE VAPOUR PRESSURE OF A SOLUTION IS DEPENDENT ON THE MOLE FRACTION OF A SOLUTE ADDED TO SOLUTION
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RAOULT'S LAW STATES THATS THE VAPOUR PRESSURE OF A SOLUTION IS EQUAL TO THE SUM OF THE VAPOUR PRESSURES OF EACH VOLATILE COMPONENT OF IT WERE PURE MULTIPLIED BY THE MOLE FRACTION OF THAT COMPONENT IN THE SOLUTION.
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FORMULAS INVOLVED IN RAOULT'S LAW....
Pr = PA+PB
WHERE,
PA=PA°.XA
AND
PB=PB°.XB
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Answer:
Question:-
describe raoult's law?
Raoult’s law states that a solvent’s partial vapour pressure in a solution (or mixture) is equal or identical to the vapour pressure of the pure solvent multiplied by its mole fraction in the solution.
Raoult’s law states that a solvent’s partial vapour pressure in a solution (or mixture) is equal or identical to the vapour pressure of the pure solvent multiplied by its mole fraction in the solution.Mathematically, Raoult’s law equation is written as;Psolution = ΧsolventP⁰solvent
solventWhere,
Psolution = vapour pressure of the solution
Χsolvent = mole fraction of the
solventP0solvent = vapour pressure of the pure solvent
We will further understand the principle behind the law by looking at the example below.Consider a solution of volatile liquids A and B in a container. Because A and B are both volatile, there would be both particles of A and B in the vapour phase.
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Explanation:
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