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describe raults law?

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Answered by vampire002
2
QUESTION :

describe raoult's law

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ANSWER :

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RAOULT'S LAW .....

RAOULT'S LAW IS A LAW THAT RELATED THE THE VAPOUR PRESSURE OF A SOLUTION IS DEPENDENT ON THE MOLE FRACTION OF A SOLUTE ADDED TO SOLUTION

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RAOULT'S LAW STATES THATS THE VAPOUR PRESSURE OF A SOLUTION IS EQUAL TO THE SUM OF THE VAPOUR PRESSURES OF EACH VOLATILE COMPONENT OF IT WERE PURE MULTIPLIED BY THE MOLE FRACTION OF THAT COMPONENT IN THE SOLUTION.

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FORMULAS INVOLVED IN RAOULT'S LAW....

Pr = PA+PB

WHERE,

PA=PA°.XA

AND

PB=PB°.XB

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Answered by MaTaehyung
1

Answer:

Question:-

describe raoult's law?

\bf\purple{Answer }

Raoult’s law states that a solvent’s partial vapour pressure in a solution (or mixture) is equal or identical to the vapour pressure of the pure solvent multiplied by its mole fraction in the solution.

Raoult’s law states that a solvent’s partial vapour pressure in a solution (or mixture) is equal or identical to the vapour pressure of the pure solvent multiplied by its mole fraction in the solution.Mathematically, Raoult’s law equation is written as;Psolution = ΧsolventPsolvent

solventWhere,

Psolution = vapour pressure of the solution

Χsolvent = mole fraction of the

solventP0solvent = vapour pressure of the pure solvent

We will further understand the principle behind the law by looking at the example below.Consider a solution of volatile liquids A and B in a container. Because A and B are both volatile, there would be both particles of A and B in the vapour phase.

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Explanation:

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