Question

describe relation between van't Hoff factor(i) and Alpha​

Answer 1

Answer:

Explanation:

The relationship between the van't Hoff factor i and the degree of dissociation α is

α= i-1/n-1

for association

α= i-1/1/n-1

Answer 2

Explanation:

$\sf The\: relation\:between\: vant \: Hoff \: factor \: and \: \alpha \: is \\ \\ \sf i = \alpha n + 1 - \alpha \\ \\ \sf i.e. \: i = 1 + \alpha (n-1)$

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