Question

Describe the chemistry of lassaigne's test for the detection of nitrogen.

Answer 1

Halogens present in an organic compound forms sodium halide on fusion with sodium metal. Sodium halide extracted with water can be easily identified by adding silver nitrate solution after acidifying with dil. HNO3.

Halogens present in an organic compound forms sodium halide on fusion with sodium metal. Sodium halide extracted with water can be easily identified by adding silver nitrate solution after acidifying with dil. HNO3. If chlorine is present, a white curdy precipitate soluble in ammonium hydroxide solution is formed.

Halogens present in an organic compound forms sodium halide on fusion with sodium metal. Sodium halide extracted with water can be easily identified by adding silver nitrate solution after acidifying with dil. HNO3. If chlorine is present, a white curdy precipitate soluble in ammonium hydroxide solution is formed.Na + Cl → NaClNaCl + AgNO3 → AgCl + NaNO3

Halogens present in an organic compound forms sodium halide on fusion with sodium metal. Sodium halide extracted with water can be easily identified by adding silver nitrate solution after acidifying with dil. HNO3. If chlorine is present, a white curdy precipitate soluble in ammonium hydroxide solution is formed.Na + Cl → NaClNaCl + AgNO3 → AgCl + NaNO3If bromine is present, an yellowish white precipitate sparingly soluble in ammonium hydroxide solution is formed.

Halogens present in an organic compound forms sodium halide on fusion with sodium metal. Sodium halide extracted with water can be easily identified by adding silver nitrate solution after acidifying with dil. HNO3. If chlorine is present, a white curdy precipitate soluble in ammonium hydroxide solution is formed.Na + Cl → NaClNaCl + AgNO3 → AgCl + NaNO3If bromine is present, an yellowish white precipitate sparingly soluble in ammonium hydroxide solution is formed.Na + Br → NaBrNaBr + AgNO3 → AgBr + NaNO3

Halogens present in an organic compound forms sodium halide on fusion with sodium metal. Sodium halide extracted with water can be easily identified by adding silver nitrate solution after acidifying with dil. HNO3. If chlorine is present, a white curdy precipitate soluble in ammonium hydroxide solution is formed.Na + Cl → NaClNaCl + AgNO3 → AgCl + NaNO3If bromine is present, an yellowish white precipitate sparingly soluble in ammonium hydroxide solution is formed.Na + Br → NaBrNaBr + AgNO3 → AgBr + NaNO3If iodine is present, an yellow precipitate insoluble in ammonium hydroxide solution is formed.

Halogens present in an organic compound forms sodium halide on fusion with sodium metal. Sodium halide extracted with water can be easily identified by adding silver nitrate solution after acidifying with dil. HNO3. If chlorine is present, a white curdy precipitate soluble in ammonium hydroxide solution is formed.Na + Cl → NaClNaCl + AgNO3 → AgCl + NaNO3If bromine is present, an yellowish white precipitate sparingly soluble in ammonium hydroxide solution is formed.Na + Br → NaBrNaBr + AgNO3 → AgBr + NaNO3If iodine is present, an yellow precipitate insoluble in ammonium hydroxide solution is formed.Na + I → NaI

Halogens present in an organic compound forms sodium halide on fusion with sodium metal. Sodium halide extracted with water can be easily identified by adding silver nitrate solution after acidifying with dil. HNO3. If chlorine is present, a white curdy precipitate soluble in ammonium hydroxide solution is formed.Na + Cl → NaClNaCl + AgNO3 → AgCl + NaNO3If bromine is present, an yellowish white precipitate sparingly soluble in ammonium hydroxide solution is formed.Na + Br → NaBrNaBr + AgNO3 → AgBr + NaNO3If iodine is present, an yellow precipitate insoluble in ammonium hydroxide solution is formed.Na + I → NaINaI + AgNO3 → AgI + NaNO3

Halogens present in an organic compound forms sodium halide on fusion with sodium metal. Sodium halide extracted with water can be easily identified by adding silver nitrate solution after acidifying with dil. HNO3. If chlorine is present, a white curdy precipitate soluble in ammonium hydroxide solution is formed.Na + Cl → NaClNaCl + AgNO3 → AgCl + NaNO3If bromine is present, an yellowish white precipitate sparingly soluble in ammonium hydroxide solution is formed.Na + Br → NaBrNaBr + AgNO3 → AgBr + NaNO3If iodine is present, an yellow precipitate insoluble in ammonium hydroxide solution is formed.Na + I → NaINaI + AgNO3 → AgI + NaNO3