Describe the construction of Daniel cell. Write electrode half reactions and net cell reaction in Daniel cell.
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Answer:
The separation of half reaction is the basis for the construction of Daniel cell. It consists of two half cells. Oxidation half cell: The metallic zinc strip that dips into an aqueous solution of zinc sulphate taken in a beaker. Reduction half cell: A copper strip that dips into an aqueous solution of copper sulphate taken in a beaker. Joining the half cell: The zinc and copper strips are externally connected using a wire through a switch (k) and a load (example: volt meter). The electrolytic solution present in the cathodic and anodic compartment are connected using an inverted U tube containing a agar-agar gel mixed with an inert electrolyte such as Kl1, Na2SO4 etc., The ions of inert electrolyte do not react with other ions present in the half cells and they are not either oxidised (or) reduced at the electrodes. The solution in the salt bridge Voltmeter cannot get poured out, but through which the ions can move into (or) out of the half cells. When the switch (k) closes the circuit, the electrons flows from zinc strip to copper strip. This is due to the following redox reactions which are taking place at the respective electrodes. Read more on Sarthaks.com - https://www.sarthaks.com/892595/describe-the-construction-of-daniel-cell-write-the-cell-reaction