Describe the effect of:
(a) addition of
.
(b) addition of
.
(c) removal of C.
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The given reaction is as follows
(a) According to the Lechatelier's principle, on addition of , the “equilibrium” of the reaction given will “shift” in the “forward reaction”.
(b) On adding of , the “equilibrium” will change in the “backward direction”.
(c) On removing CO, the “equilibrium” will change in the “backward direction”.
(d) On removing , the “equilibrium” will change in the “forward direction”.
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The given reaction is as follows
2{ H }_{ 2 }(g)\quad +\quad CO(g)\quad \leftrightarrow \quad { CH }_{ 3 }OH2H2(g)+CO(g)↔CH3OH
(a) According to the Lechatelier's principle, on addition of { H }_{ 2 }H2 , the “equilibrium” of the reaction given will “shift” in the “forward reaction”.
(b) On adding of C{ H }_{ 3 }OHCH3OH , the “equilibrium” will change in the “backward direction”.
(c) On removing CO, the “equilibrium” will change in the “backward direction”.
(d) On removing C{ H }_{ 3 }OHCH3OH , the “equilibrium” will change in the “forward direction”.
2{ H }_{ 2 }(g)\quad +\quad CO(g)\quad \leftrightarrow \quad { CH }_{ 3 }OH2H2(g)+CO(g)↔CH3OH
(a) According to the Lechatelier's principle, on addition of { H }_{ 2 }H2 , the “equilibrium” of the reaction given will “shift” in the “forward reaction”.
(b) On adding of C{ H }_{ 3 }OHCH3OH , the “equilibrium” will change in the “backward direction”.
(c) On removing CO, the “equilibrium” will change in the “backward direction”.
(d) On removing C{ H }_{ 3 }OHCH3OH , the “equilibrium” will change in the “forward direction”.
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