Question

describe the electrical diagram consisting of a galvanic cell, a rheostat and two light bulbs connected in parallel. Turn on the ammeter in this diagram so that the current flowing through the second bulb and the voltmeter indicating the rheostat voltage are displayed.

Answer 1

Explanation:

Here the circuit in which a resistor of resistance 4Ω is attached in series and two resistors of resistance 8Ω are attached in parallel. Also, Ammeter and voltmeter attached in the circuit in series and parallel respectively.

Now,

Maximum power of each resistor is 16W

4Ω resistor is joined in series with circuit .

so, Power=i2R , here i is current through resistor of resistance R

$$16=i^{2}\ast 4Ω$$

i = 2A

Now, 2A is passing through parallel resistors of resistance 8Ω.

we know, in parallel potential difference be constant so,

current divides two part , due to 

Answer 2

hope it helps you out a little bit