Chemistry, asked by zeem8972, 3 months ago

describe the electrolysis of molten lead [ii] bromide using platinum electrodes state the equation at each electrodes

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Answered by s02371joshuaprince47
4

Answer:

Pb2+(l) + 2e– ==> Pb(l) This is a reduction reaction because the lead ions gain electrons. The negative bromide ions are attracted to the positive anode electrode and discharged to form bromine vapour.

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