describe the main features of the bohr's model of atoms draw a neat and labelled drive gram of energy
Answers
★ Some key points
1. Atom has centre called nucleus.
2. electron revolves only in fixed circular orbits with fixed energy and fixed velocity.
3. Quantization condition :- electrons revolve only in those circular orbits for which the angular momentum (L) is integral Multiple of h/2π .
→ L = nh/2π = n = integer
n = shell number
→ n = 1 → K
→ n = 2 → L
→ n = 3 → M
→ n = 4 → N
→ Angular momentum = mvr sin∅
→ ∅ = 90° = L = mvr
As mentioned above
→ L = nh/2π
→ mvr = nh/2π ( Bohr's Quantization condition)
h = plank's constant
h = 6.636 × 10^-34 JS
4. while revolving the electrostatic force between electron and nucleus provides centripetal force.
→ Fe = Fc
→ Fe = Kq1q2/r²
→ charge on nucleus = +ze
→ Fc = mv²/r
k = constant ( 1/4πE0)
F = 1/4πE0 eze/r² = mv²/r
5. while revolving in a particular orbit electrons neither gains energy not losses energy.
→ energy of an orbit is fixed
shells → stationary energy level.
By using following equations we can calculate the radius ( r ) , velocity ( v) , kinetic energy (K.E) , potential energy (P.E) and total energy (T.E) of electron.
→ r = n²h²E0/πmze²
→ v = ze²/2hE0
→ K.E = (me⁴/ 8h²E0² ) × z²/n²
→ P.E = -2 (me⁴/ 8h²E0² ) × z²/n²
→ T.E = P.E + K.E
6. electron can accept energy and loose energy .
→ If an electron accepts energy it jumps to higher energy level → excitation of electron
→If electron loses energy it receds to lower energy level → deexcitation of electron
→ An electron gains or loses only those energy which are equal to difference in two energy levels.
→ E1 + ∆E = E2
→ E1 + ∆ E = E3
Now coming to the drawbacks
1. Bohr's model is valid for only single electron specie. ex - H , He+ etc.
2. Bohr considered electron as a moving particle
which later De - broglie gave his hypothesis that every microscopic moving particle is a wave , whose wavelength is given by
3. Bohr measured position of electron and velocity of electron .
but according to the Heisenberg uncertainty principle - The exact and simultaneous determination of position and momentum of a moving microscopic particle is impossible.
∆P • ∆x = h/4π
∆P = momentum measure error
∆x = position measure error
4. Spectral lines , they show splitting in magnetic and electric field ( Zeeman and stark effect)
5. Ultra fine spectrum
Solution of E . Schodinger wave equation gives variables . → represent position of electron → those positions whose probability of finding electron is maximum