Question

describe the mass and volume of oxygen required for the complete combustion of 20 grams of ethane c2h6

Answer 1

Answer:

DO WITH THE HELP OF BELOW MODEL

Explanation:

Given that 

Mass of propane =8.8 g

Number of moles =molar massmass=448.8=0.2 mol

Now,

C3H8 + 5O2 ⟶ 3CO2 + 4H2O

1 mole of propane requires 5×{22.4} litre O2.

So, 0.2 mole propane requires 5×{22.4}×{0.2} = 22.4 litre O2