describe the method of balancing chemical equation by taking an example
Answers
H2 + O2 --> H2O (unbalanced equation for formation of water)
This equation can be balanced by using certain steps as mentioned below.
Step I: list the number of atoms of each element present on both sides of arrow.
Reactant. Product
H. 2. 2
O. 2. 1
Step II: Begin balancing with the compound having maximum number of atoms. Following this rule we select H2O. Here there are 2 oxygen atoms on the reactant side but only 1 oxygen atom on the product side. So equation is unbalanced. In order to balance we need to do following step.
Reactant. Product
Initial oxygen. 2. 1
atom
To balance. 2. 1×2
So the equation stands out to be
H2 + O2 --> 2H2O
Step III: After balancing oxygen the equation is H2 + O2 à 2H2O. So now we need to balance hydrogen atom.
Reactant. Product
Initial hydrogen. 2. 4
atom
To balance. 2×2. 4
So the final equation stands out to be
◆2H2 + O2 --> 2H2O.
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Answer:
We take the reaction of formation of water.
H2 + O2 --> H2O (unbalanced equation for formation of water)
This equation can be balanced by using certain steps as mentioned below.
Step I: list the number of atoms of each element present on both sides of arrow.
Reactant. Product
H. 2. 2
O. 2. 1
Step II: Begin balancing with the compound having maximum number of atoms. Following this rule we select H2O. Here there are 2 oxygen atoms on the reactant side but only 1 oxygen atom on the product side. So equation is unbalanced. In order to balance we need to do following step.
Reactant. Product
Initial oxygen. 2. 1
atom
To balance. 2. 1×2
So the equation stands out to be
H2 + O2 --> 2H2O
Step III: After balancing oxygen the equation is H2 + O2 à 2H2O. So now we need to balance hydrogen atom.
Reactant. Product
Initial hydrogen. 2. 4
atom
To balance. 2×2. 4
So the final equation stands out to be
◆2H2 + O2 --> 2H2O.
Explanation: