Question

Describe the motion of a body which is accelerating at a constant rate of 10 m/s. If the body starts from rest, how much distance will it cover in 2s?

Answer 1

Given, a = 10m/s .
t = 2s.
The body stars from rest, u = 0 .

From, Equations of motion;
v = u + at.

⇒v = 0 + 10 * 2
⇒v = 10 * 2
⇒v = 20 m/s

Now, s = vt - 1/2at²
⇒s = 20(2) - 1/2(10)(2²)
⇒ s = 40 - 20
⇒s = 20 m.

( or)
⇒s = ut + ½at²
⇒s = (0)2 + 1/2(10)(2²)
⇒s= 20m

The distance travelled = 20m .

Answer 2

Hey!

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Acceleration (a) = 10 m/s
Initial velocity (u) = 0
Time (t) = 2s
Distance travelled (s) = ?

Final velocity = ?

v = u + at
v = 0 + 10×2
v= 20 m/s

Now,

v^2 - u^2 = 2as
(20)^2 = 2 × 10 × s
400 = 20 s
400/20 = s

s = 20 m

Distance travelled is 200 m.


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Hope it helps...!!!