Question

describe the motion of a body which is accelerating at a constant rate of 10m/s.If the body starts from rest,how much distance will it cover in 2 secs

Answer 1

we know that s= ut+1/2at^2.:::: so putting the values of t, a &u as 2,10,0 we get (s=20m)

Answer 2

A body starts from rest means initial velocity is 0 m/s and travelling with an acceleration of 4 m/s².

We have to find the distance travelled by the body in the 4th second.

We know that distance covered by body in nth second is given by-

Sn = u + a/2 (2n - 1)

Here; n = 4 sec, u = 0 m/s and a is 4 m/s².

Let us assume that the distance covered in the 4th second is x km.

Substitute the known values in the above formula,

→ x = 0 + 4/2 (2*4 - 1)

→ x = 0 + 2 (8 - 1)

→ x = 0 + 2(7)

→ x = 0 + 14

→ x = 14

As, the x is the distance covered in 4th second.

Therefore, the distance covered by the body in the 4th second is 14 m.