Question

Describe the motion of a body which is accelerating at a constant rate of 10ms-2. If the body starts from rest,how much distance will it cover in 2s ?

Answer 1

As per Question:-

Initial Velocity = 0 m/s

Acceleration = 10 m/s²

time = 2 s

⇒ v = u + at

⇒ v = 0 + 10 x 2

⇒ v = 20 m/s

Again, For Distance covered,

⇒ S = ut + 1/2 at²

⇒ S = 0 + 1/2 x 10 x (2)²

⇒ S = 5 x 4 m

∴ S = 20 m

Answer 2

Given :-

Acceleration (a)  = 10 m/s²

Time (t) = 2s

As when body starts from rest then it have only Final Velocity, Its Initial Velocity becomes Zero.

∴ Initial Velocity = 0 m/s

⇒ V = u + at

⇒ V = 0 + 10 x 2

⇒ V = 20 m/s

Here we will apply third equation of Motion to find distance transverse.

⇒ v² = u² + 2aS

⇒ 20² = 0² + 2 x 10 x S

⇒ 400 = 20 x S

⇒ S = 400/20

∴ S = 20 m

Hence, Distance tranversed = S = 20 m