Question

Describe the nate of image formed when the object is placed at a distance of 22cm from a concave mirror of focal length 11 cm??




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Answer 1

Answer:

Object distance (u) = -22 cm

focal length = 11 cm

using formula

$\frac{1}{f} = \frac{1}{u}+ \frac{1}{v}$

$\frac{1}{11} = \frac{1}{-22 }+ \frac{1}{v}$

$\frac{1}{v} = \frac{1}{11} + \frac{1}{22}\\\\\frac{1}{v} = \frac{2}{22} +\frac{1}{22}\\\frac{1}{v} =\frac{3}{22}\\ v = \frac{22}{3}\\ v = 7.142 cm$

Image will be formed behind the mirror ;

Smaller than the size of object ;

virual and inverted ;

Explanation: