Question

describe the nature of root of the equation 2xsquare=7x–1
fast

​

Answer 1

Answer:

The roots are real and unequal

Step-by-step explanation:

$2x {}^{2} - 7x - 1 = 0$

Nature of the root can be find my finding the value of D. and

$d = {b}^{2} \: - 4ac$

So

So D = (-7)(-7) - 4x 2 x (-1)

So D = (-7)(-7) - 4x 2 x (-1)D = 49+8 = 57 >0

So D = (-7)(-7) - 4x 2 x (-1)D = 49+8 = 57 >0Hence the roots are real and unequal

Answer 2

Answer:

${2x}^{2} - 7x + 1 = 0$

$nature \: of \: root \: = {b}^{2} - 4ac$

$here \: a = 2 \: b = { - 7} \: c = 1$

$so \: nature \: of \: root \: = { - 7}^{2} - 4 \times 2 \times 1$

$nature \: of \: root \: = 49 - 8$

$nature \: of \: root \: = + 41 > 0$

So, roots are real