Describe the potentiometer experiment to determine the internal resistance of a cell.
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Explanation:
In a potentiometer experiment, it is found that no current passes through the galvanometer when the terminals of the cell are connected across 52cm of the potentiometer wire. If the cell is shunted by a resistance of 5Ω, a balance is found when the cell is connected across 40cm of the wire.
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Explanation:
Potentiometer can be used to measure the internal resistance of the cell. A cell of emf E is connected across the resistance box through key K1. When key K1 is opened galvanometer shows deflection at the balancing length l1. If both keys are closed, then balancing point is obtained at length l2 (l2 < l1).
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