Chemistry, asked by minyunseok01, 13 hours ago

Describe the preparation of 600mL of 0.01 M KH(IO3)2 (potassium hydrogen iodate) solution MW = 389.97 g/mol from primary standard solid. (answer : 2.34 g KH(IO3)2 and diluted with 600 mL distilled water.)​

Answers

Answered by dakshkoche62
2

Answer:

iodate is the anion with the formula IO−

3. It is the most common form of iodine in nature, as it comprises the major iodine-containing ores.[1] Iodide salts are often colorless.

Answered by Sugarstar6543
25

Explanation:

Potassium Biiodate

Potassium Hydrogen Diiodate

Chemical Formula KH(IO3)2

Formula Weight 389.91

Equivalent Weight

(oxidimetric) 32.49 (Molar = 12 Normal)

Equivalent Weight

(basimetric) 389.91 (Molar = Normal)

CAS No. 13455-24-8

Potassium Biiodate is a primary standard substance that can be used as a basimetric as well as an oxidimetric standard. In addition to its versatility, it has the advantage of a high equivalent weight, especially when used to standardize bases. Its disadvantages are that it is relatively expensive, and only sparingly and slowly soluble in water. The reaction for its use as an oxidimetric standard is as follows:

KH(IO3)2 + 11 H+ + 10 I- → 6 I2 + K+ + 6 H2O

The Iodine thus generated in the presence of Iodide and acid can be used to assay various reducing agents, such as Sodium Thiosulfate, using Starch indicator.

RICCA CHEMICAL COMPANY Potassium Biiodate titrants are intended for use as oxidimetric standards, and the normality is based on the equivalent weight in oxidation-reduction reactions.

hope it helps you please make me as brainist

Similar questions