Describe the preparation of 750ml of 6M H3PO4 from commercial reagent that is 86% H3PO4 (w/w) and has a specific gravity 1.71
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Number of moles of acid required = Volume in litres x molarity
= (750/1000) x 6
= 4.5 moles
Mass of acid = Molar mass x No. of Moles
= 98 x 4.5 = 441 g
100ml of commercial reagent has mass
= 100x1.71
= 171g
Mass of acid = (86/100) x 171
= 147.06g
If 147.06 g of acid is in 100ml of reagent
Therefore, 441g of acid will be in = (441x100)/147.06 = 300ml
PREPARATION
Take 300ml of reagent in a 750ml volumetric flask
Add water slowly with little shaking until the volume is about 750ml
Continue adding water carefully until in reaches the 750ml mark
This solution will be 6M H3PO4 Acid
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