Chemistry, asked by hereforhelp98, 9 months ago

Describe the preparation of pure, dry sample of silver chloride from aqueous silver nitrate and dilute hydrochloric acid.​

Answers

Answered by lokesh1262
7

Answer:

Silver Chloride

AgNO3 combines with chloride ions and forms AgCl precipitate.

Properties

AgCl is obtained as a white precipitate

AgCl is insoluble in water.

It is soluble in aqueous ammonia

Silver Nitrate

In the preparation of silver nitrate dilute nitric acid is used. Silver combines with HNO3 and forms silver nitrate.

Properties

It is colorless and is soluble in water.

On heating AgNO3 decomposes and forms silver, nitrogen dioxide and oxygen.

Answered by ahmad6137
2

Answer: By the reacion of crystalisation

Explanation:

When the reaction of Silver nitrate and dilute hydrochloric acid will de don so in the product we will get aqueous solution of sodium chloride and nitric acid. Next, we will separate sodium chloride from nitric acid by the process of filtration. Then we will heat the mixture of sodium chloride and then we will leave it unit the crystals of sodium chloride are obtained.

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