Chemistry, asked by yogesh1372, 1 year ago

Describe the procedure for preparation of 1 normal Oxalic acid

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Answered by sourav9927
1
1 mole of oxalic acid means molecular weight gram of acid (90 g = 1 mol ). If you dissolve 90 g of acid in 1 liter of water then it will be 1 normal (N). To make 0.1 N you need to dissolve 9 g ofoxalic acid in 1 liter. If you want to make 1 Molar acid you should dissolve 90 g of acid in 1 kg of water.
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