Question

Describe the roots of quadratic equation using the discriminant

1) 3x^2+8x-8=0
2) 7x^2-10x+1=0

Answer 1

Step-by-step explanation:

$1) \: 3 {x}^{2} + 8x + - 8 = 0 \\ dicriminant \: = {b}^{2} - 4ac \: \\ = {8}^{2} - 4(3)( - 8) = 64 + 96 \\ = 160 \\ 2)7 {x}^{2} - 10x + 1 = 0 \\ discriminant = {( - 10)}^{2} - 4(7)(1) \\ = 100 - 28 \\ = 72$