Physics, asked by jon888, 9 months ago

Describe the types of bonds and orbitals in Urea, (NH2)2CO
hybridization concept ​

Answers

Answered by roginroy2004
2

Answer:

The structural formula of urea is (NH2)C=O

The 2 (NH2) groups are joined to central carbon with a single bond (sigma bond). And the central carbon is attached to oxygen atom with a double bond (1 sigma bond & 1 pi bond).

So all total central carbon has 2 single bonds and 1 double bond. This concludes that central carbon has 3 sigma bonds and 1 pi bond

As there is 3 sigma bonds so the hybridisation is sp² so 1 s-orbital and 2 p-orbitals will hybridise and the remaining 1 unhybridised p-orbital will form pi bond.

Explanation:

Answered by siddhantprasad8
2

The structural formula of urea is (NH2)C=O

The 2 (NH2) groups are joined to central carbon with a single bond (sigma bond). And the central carbon is attached to oxygen atom with a double bond (1 sigma bond & 1 pi bond).

So all total central carbon has 2 single bonds and 1 double bond. This concludes that central carbon has 3 sigma bonds and 1 pi bond.

As there is 3 sigma bonds so the hybridisation is sp² so 1 s-orbital and 2 p-orbitals will hybridise and the remaining 1 unhybridised p-orbital will form pi bond.

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