Describe the types of bonds and orbitals in Urea, (NH2)2CO
hybridization concept
Answers
Answer:
The structural formula of urea is (NH2)C=O
The 2 (NH2) groups are joined to central carbon with a single bond (sigma bond). And the central carbon is attached to oxygen atom with a double bond (1 sigma bond & 1 pi bond).
So all total central carbon has 2 single bonds and 1 double bond. This concludes that central carbon has 3 sigma bonds and 1 pi bond
As there is 3 sigma bonds so the hybridisation is sp² so 1 s-orbital and 2 p-orbitals will hybridise and the remaining 1 unhybridised p-orbital will form pi bond.
Explanation:
The structural formula of urea is (NH2)C=O
The 2 (NH2) groups are joined to central carbon with a single bond (sigma bond). And the central carbon is attached to oxygen atom with a double bond (1 sigma bond & 1 pi bond).
So all total central carbon has 2 single bonds and 1 double bond. This concludes that central carbon has 3 sigma bonds and 1 pi bond.
As there is 3 sigma bonds so the hybridisation is sp² so 1 s-orbital and 2 p-orbitals will hybridise and the remaining 1 unhybridised p-orbital will form pi bond.