Chemistry, asked by summisingh, 5 months ago

describe the various conformation of 1,2 dimethly cyclohexane in hindi​

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Answered by biswasahoo
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Answer:

Discuss the the relative conformation analysis of 1,2-dimethylcyclohexane.

If we consider cis isomer of 1,2-dimethylcyclohexane, the e,a and a,e both conformer is

optically active ads no element of symmetry present. In both conformer three extra gauche

butane interaction present and hence both conformer is equally populated. But on flipping it

gives the mirror image conformer and hence they are enantimers of each other. So due to

internal compensation net optical rotation is zero and they are called invertomer.

Theoritically enantiomers should be separable at very low temperature but in practice there

are no such reports.

.

Whereas both the a,a and e,e conformation of trans 1,2-dimethylcyclohexane is optically

active , can exists in enantiomers and they are resolvable . Both the a,a and e,e conformer

contain a C2 axis passing through C1-C2 and C4-C5 bond. It is obvious that in a,a conformer

there is four gauche butane interaction whereas in e,e conformer there is only two gauche

butane interaction and hence the e,e conformer is more stable and maximum populated.

2. Discuss the relative conformation analysis of 1,3-dimethylcyclohexane.

If we look the conformation analysis of cis 1,3-dimethyl cyclohexane, both the e,e and a,a

conformer posses a sigma( σ)plane and hence it is optically inactive; no question of

resolution arises. In a,a conformer there is two extra gauche butane interaction and hence the

e, e conformer is more populated.

In case of trans isomer, both the e,a and a,e conformer contains one extra gauche butane

interaction and hence both conformer is equally populated. But ring invertion itself produces

an equivalent conformer and hence it is an example of topomerisation. The planner structure

Explanation:

symmetry and hence it is asymmetric molecule.

3. Discuss the relative conformation analysis of 1,4-dimethylcyclohexane.

Let us look at the trans isomer of 1,4-dimethylcyclohexane; both the planner structure and

puckered structure contain plane of ymmetry and hence molecule is optically inactive and

hence no question of resolution. The e,e conformer is more stable and highly populated

compared to the a,a confer as the later contain four more gauche butane interaction.

The cis isomer of 1,4-dimethylcyclohexane also contain a sigma plane passing vertically

through C1 and C4 and hence compound is optically inactive; no question of resolution. Both

the e,a and a,e conformers are equally populated and they are equivalent on ring invertion.

4.Discuss the relative stabilities of monosubstituted cyclohexane.

In case of monosubstituted cyclohexane, two different chair conformer exists-with axial

substituents called axial conformer and with equatorial substituents called equatorial

conformer. Both conformers are in rapid equilibrium by means of inversion but they will not

have same energy. In almost all cases, the conformer with axial substituents has higher

energy compared to the equatorial conformer and hence the population percentage of axial

conformer is far less than the equatorial conformer.

H

CH3

CH3

H

H CH3

H3C

H

H CH3

H3C H

H

CH3

CH3

turning upside down 120

rotation H

H

CH3

H

H3C

CH3

H

CH3

H

H

CH3

CH3

H

CH3

H

H

H3C

CH3

H

H

H3C

X

X

high energy conformation low energy conformation

axial substituent:

axial conformer

equatorial substituent:

equatorial conformer

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