Question

Described the state of oscillation if the the phase of angle is 1110 degree

Answer 1

ANGLE=1110 DEGREE

        =(3X360 DEGREE)GREATER

4th OSCILLATION

x= A sin O

v=A sin 30degree

=A 1/2

v= +A/2

phase angle 1110degree = during 4th oscillation pqangle is +a/2 and moving positive extreme