description on air cooler to prepare a file
Answers
Answer:
An air cooler works by evaporating the water. It lowers the temperature of the air using evaporative cooling. It is the addition of vapour in the air to reduce the heat. The energy needed to evaporate the water is taken from the air in the form of sensible heat, which affects the temperature of the air.
Explanation:
During the runtime of air cooler, water evaporates and increase the humidity in the air. Increase in the humidity is much favorable conditions to increase bacteria, viruses, mold in the water. Because of this reason Asthma patients should be very careful about the usage of air cooler.
An air cooler uses a combination of a fan and watered cooling mediums to pull hot air from outside. As the hot air passes through the mediums, the water absorbs the heat and evaporates, leaving cool air to be pushed out by the fan.
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Answer:
Air cooling is a method of dissipating heat. It works by expanding the surface area or increasing the flow of air over the object to be cooled, or both. An example of the former is to add cooling fins to the surface of the object, either by making them integral or by attaching them tightly to the object's surface (to ensure efficient heat transfer). In the case of the latter, it is done by using a fan blowing air into or onto the object one wants to cool. The addition of fins to a heat sink increases its total surface area, resulting in greater cooling effectiveness. There are two types of cooling pads are used in air cooling one is a honeycomb and another one is excelsior.
In all cases, the air has to be cooler than the object or surface from which it is expected to remove heat. This is due to the second law of thermodynamics, which states that heat will only move spontaneously from a hot reservoir (the heat sink) to a cold reservoir (the air).
When operating in an environment with lower air pressure like high altitude or airplane cabins, the cooling capacity has to be derated compared to that of sea level.
A rule-of-thumb formula 1 - (h/17500) = derating factor. Where h is the height over sea level in meters. And the result is the factor that should be multiplied with the cooling capacity in [W] to get the cooling capacity at the specified height over sea level.
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