Question

Descsibe isothermal process and derive expersion_for workdone, Change in internal energy, heat tansfer and Changes in enthalpy
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Answer 1

Answer:

An ideal gas by definition has no interactions between particles, no intermolecular forces, so pressre change at constant temperature does not change internal energy. ... Their internal energy changes with change in pressure, even if temperature is constant. For an ideal gas, in an isothermal process, ΔU=0=Q−W, so Q=W