Question

Deshaun invested his savings in two investment funds. The amount he
invested in Fund A was 3 times as much as the amount he invested in
Fund B. Fund A returned a 7% profit and Fund B returned a 4% profit.
How much did he invest in Fund B, if the total profit from the two funds
together was $2000?​

Answer 1

•Deshaun invested his savings in two investment funds. The amount he invested in Fund A was 3 times as much as the amount he invested in Fund B. Fund A returned a 7% profit and Fund B returned a 4% profit.

•The total profit from the two funds

together was $2000.

•Let he invest $x in fund B.

•So the investment in fund A be $3x.

•Profit in Fund A is (7*3x)/100 = 21x/100.

•Profit in Fund B is (4*x)/100 = 4x/100.

•Total profit = 25x/100 = 2000

Therefore, x = 8000

•Hence the investment in Fund B is $8000

Answer 2

He invest in Fund B $8000.

Step-by-step explanation:

Given:

Deshaun invested his savings in two investment funds. The amount he

invested in Fund A was 3 times as much as the amount he invested in

Fund B. Fund A returned a 7% profit and Fund B returned a 4% profit.

If the total profit from the two funds  together was $2000.

Now, to find the amount he invest in Fund B.

Let the amount invested in Fund B be $x.$

So, the amount invested in Fund A be $3x.$

As, the Fund B returned a 4% profit.

4% of $x$

$\frac{4}{100}\times x\\\\=\frac{4x}{100} \\\\=0.04x.$%

So, the profit of fund B = 0.04$x$.

Now, Fund A returned a 7% profit:

$7\%\ of\ 3x\\\\=\frac{7}{100}\times 3x \\\\=0.07\times 3x\\\\=0.21x$

So, the profit of fund A = 0.21$x.$

The total profits from the two funds  together was $2000.

According to question:

$0.04x+0.21x=2000\\\\0.25x=2000$

$x=\frac{2000}{0.25}$

$x=\ 8000.$

Therefore, he invest in Fund B is $8000.